Reaction: 4PH 3 (g) — P 4 (g) + 6 H 2 (g). Over a specific time period, 0.0048 mole of PH 3 is consumed in a 2.0 L container each second of the…

Reaction: 4PH3(g) –> P4 (g) + 6 H2 (g).
Over a specific time period, 0.0048 mole of PH3 is consumed in a 2.0 L container each second of the reaction. What is the rate of production of H2 in this experiment?The post Reaction: 4PH 3 (g) — P 4 (g) + 6 H 2 (g). Over a specific time period, 0.0048 mole of PH 3 is consumed in a 2.0 L container each second of the… first appeared on Nursing School Essays.